13109111 has 2 divisors, whose sum is σ = 13109112. Its totient is φ = 13109110.

The previous prime is 13109101. The next prime is 13109167. The reversal of 13109111 is 11190131.

13109111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13109111 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13109111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13109101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6554555 + 6554556.

It is an arithmetic number, because the mean of its divisors is an integer number (6554556).

Almost surely, 2^13109111 is an apocalyptic number.

13109111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13109111 is an equidigital number, since it uses as much as digits as its factorization.

13109111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27, while the sum is 17.

The square root of 13109111 is about 3620.6506321378. The cubic root of 13109111 is about 235.7894739893.

Adding to 13109111 its reverse (11190131), we get a palindrome (24299242).

The spelling of 13109111 in words is "thirteen million, one hundred nine thousand, one hundred eleven".