1310982941 has 2 divisors, whose sum is σ = 1310982942. Its totient is φ = 1310982940.

The previous prime is 1310982923. The next prime is 1310982943. The reversal of 1310982941 is 1492890131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1199236900 + 111746041 = 34630^2 + 10571^2 .

It is an emirp because it is prime and its reverse (1492890131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1310982941 - 2⁶ = 1310982877 is a prime.

Together with 1310982943, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1310982895 and 1310982904.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310982943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655491470 + 655491471.

It is an arithmetic number, because the mean of its divisors is an integer number (655491471).

Almost surely, 2^1310982941 is an apocalyptic number.

It is an amenable number.

1310982941 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310982941 is an equidigital number, since it uses as much as digits as its factorization.

1310982941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 38.

The square root of 1310982941 is about 36207.4984084789. The cubic root of 1310982941 is about 1094.4577817720.

The spelling of 1310982941 in words is "one billion, three hundred ten million, nine hundred eighty-two thousand, nine hundred forty-one".