131100000000203 has 4 divisors (see below), whose sum is σ = 141184615384848. Its totient is φ = 121015384615560.

The previous prime is 131100000000149. The next prime is 131100000000241. The reversal of 131100000000203 is 302000000001131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131100000000203 - 2¹⁰ = 131099999999179 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131100000900203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5042307692303 + ... + 5042307692328.

It is an arithmetic number, because the mean of its divisors is an integer number (35296153846212).

Almost surely, 2^{131100000000203} is an apocalyptic number.

131100000000203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

131100000000203 is a deficient number, since it is larger than the sum of its proper divisors (10084615384645).

131100000000203 is a wasteful number, since it uses less digits than its factorization.

131100000000203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10084615384644.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 131100000000203 its reverse (302000000001131), we get a palindrome (433100000001334).

The spelling of 131100000000203 in words is "one hundred thirty-one trillion, one hundred billion, two hundred three", and thus it is an aban number.