Base | Representation |
---|---|
bin | 11101110011110000011010… |
… | …001100000011010111000100 |
3 | 122012012001001212210120021021 |
4 | 131303300122030003113010 |
5 | 114140420320401011322 |
6 | 1142454303540000524 |
7 | 36420443510651020 |
oct | 3563603214032704 |
9 | 565161055716237 |
10 | 131100021110212 |
11 | 38855230167680 |
12 | 1285408b990144 |
13 | 581c8a9841cbb |
14 | 24533bc39d380 |
15 | 102532bd194c7 |
hex | 773c1a3035c4 |
131100021110212 has 48 divisors (see below), whose sum is σ = 286049840993280. Its totient is φ = 51075531856800.
The previous prime is 131100021110189. The next prime is 131100021110249. The reversal of 131100021110212 is 212011120001131.
It is a happy number.
131100021110212 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3416614 + ... + 16549117.
It is an arithmetic number, because the mean of its divisors is an integer number (5959371687360).
Almost surely, 2131100021110212 is an apocalyptic number.
It is an amenable number.
131100021110212 is an abundant number, since it is smaller than the sum of its proper divisors (154949819883068).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131100021110212 is a wasteful number, since it uses less digits than its factorization.
131100021110212 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19987072 (or 19987070 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 131100021110212 its reverse (212011120001131), we get a palindrome (343111141111343).
The spelling of 131100021110212 in words is "one hundred thirty-one trillion, one hundred billion, twenty-one million, one hundred ten thousand, two hundred twelve".
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