Base | Representation |
---|---|
bin | 111101000011000101… |
… | …1001111100001111111 |
3 | 110112101120222202222121 |
4 | 1322012023033201333 |
5 | 4121443112104043 |
6 | 140120534223411 |
7 | 12320532400645 |
oct | 1720613174177 |
9 | 415346882877 |
10 | 131100113023 |
11 | 50665661350 |
12 | 214a91b4b67 |
13 | c493a94a99 |
14 | 64b9637195 |
15 | 362471cded |
hex | 1e862cf87f |
131100113023 has 4 divisors (see below), whose sum is σ = 143018305128. Its totient is φ = 119181920920.
The previous prime is 131100113017. The next prime is 131100113099. The reversal of 131100113023 is 320311001131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131100113023 - 229 = 130563242111 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131100112988 and 131100113006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131100113323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5959096036 + ... + 5959096057.
It is an arithmetic number, because the mean of its divisors is an integer number (35754576282).
Almost surely, 2131100113023 is an apocalyptic number.
131100113023 is a deficient number, since it is larger than the sum of its proper divisors (11918192105).
131100113023 is a wasteful number, since it uses less digits than its factorization.
131100113023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11918192104.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 131100113023 its reverse (320311001131), we get a palindrome (451411114154).
The spelling of 131100113023 in words is "one hundred thirty-one billion, one hundred million, one hundred thirteen thousand, twenty-three".
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