13110033324231 has 12 divisors (see below), whose sum is σ = 18981909830520. Its totient is φ = 8719162972080.

The previous prime is 13110033324181. The next prime is 13110033324253. The reversal of 13110033324231 is 13242333001131.

13110033324231 is a `hidden beast` number, since 1 + 3 + 1 + 100 + 3 + 3 + 324 + 231 = 666.

It is not a de Polignac number, because 13110033324231 - 2¹⁵ = 13110033291463 is a prime.

It is a super-2 number, since 2×13110033324231² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13110033324195 and 13110033324204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110033824231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1738266360 + ... + 1738273901.

It is an arithmetic number, because the mean of its divisors is an integer number (1581825819210).

Almost surely, 2^{13110033324231} is an apocalyptic number.

13110033324231 is a deficient number, since it is larger than the sum of its proper divisors (5871876506289).

13110033324231 is a wasteful number, since it uses less digits than its factorization.

13110033324231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3476540686 (or 3476540683 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 27.

Adding to 13110033324231 its reverse (13242333001131), we get a palindrome (26352366325362).

The spelling of 13110033324231 in words is "thirteen trillion, one hundred ten billion, thirty-three million, three hundred twenty-four thousand, two hundred thirty-one".