131100442134343 has 6 divisors (see below), whose sum is σ = 144102138875072. Its totient is φ = 119182220122020.

The previous prime is 131100442134331. The next prime is 131100442134419. The reversal of 131100442134343 is 343431244001131.

It is not a de Polignac number, because 131100442134343 - 2⁹ = 131100442133831 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131100442134299 and 131100442134308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131100442134643) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 541737364071 + ... + 541737364312.

Almost surely, 2^{131100442134343} is an apocalyptic number.

131100442134343 is a deficient number, since it is larger than the sum of its proper divisors (13001696740729).

131100442134343 is a wasteful number, since it uses less digits than its factorization.

131100442134343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1083474728405 (or 1083474728394 counting only the distinct ones).

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 131100442134343 its reverse (343431244001131), we get a palindrome (474531686135474).

The spelling of 131100442134343 in words is "one hundred thirty-one trillion, one hundred billion, four hundred forty-two million, one hundred thirty-four thousand, three hundred forty-three".