13110100023041 has 4 divisors (see below), whose sum is σ = 14982971454912. Its totient is φ = 11237228591172.

The previous prime is 13110100022989. The next prime is 13110100023047. The reversal of 13110100023041 is 14032000101131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13110100023041 is a prime.

It is a super-2 number, since 2×13110100023041² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13110100023047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 936435715925 + ... + 936435715938.

It is an arithmetic number, because the mean of its divisors is an integer number (3745742863728).

Almost surely, 2^{13110100023041} is an apocalyptic number.

It is an amenable number.

13110100023041 is a deficient number, since it is larger than the sum of its proper divisors (1872871431871).

13110100023041 is an equidigital number, since it uses as much as digits as its factorization.

13110100023041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1872871431870.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13110100023041 its reverse (14032000101131), we get a palindrome (27142100124172).

The spelling of 13110100023041 in words is "thirteen trillion, one hundred ten billion, one hundred million, twenty-three thousand, forty-one".