131101002015 has 16 divisors (see below), whose sum is σ = 214877740896. Its totient is φ = 68215155200.

The previous prime is 131101002013. The next prime is 131101002031. The reversal of 131101002015 is 510200101131.

It is not a de Polignac number, because 131101002015 - 2¹ = 131101002013 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a junction number, because it is equal to n+sod(n) for n = 131101001985 and 131101002003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131101002013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 106585566 + ... + 106586795.

It is an arithmetic number, because the mean of its divisors is an integer number (13429858806).

Almost surely, 2^131101002015 is an apocalyptic number.

131101002015 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

131101002015 is a deficient number, since it is larger than the sum of its proper divisors (83776738881).

131101002015 is a wasteful number, since it uses less digits than its factorization.

131101002015 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 213172410.

The product of its (nonzero) digits is 30, while the sum is 15.

Adding to 131101002015 its reverse (510200101131), we get a palindrome (641301103146).

The spelling of 131101002015 in words is "one hundred thirty-one billion, one hundred one million, two thousand, fifteen".