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13110100414111 = 13241990114071
BaseRepresentation
bin1011111011000110111011…
…1000001100111010011111
31201102022110102212001220201
42332301232320030322133
53204243441201222421
643514410314324331
72522113336600351
oct276615670147237
951368412761821
1013110100414111
1141a4a649a4478
1215789aa1296a7
1374137ac1244c
143347646a70d1
1517b0554b6b91
hexbec6ee0ce9f

13110100414111 has 4 divisors (see below), whose sum is σ = 13111090541424. Its totient is φ = 13109110286800.

The previous prime is 13110100414091. The next prime is 13110100414139. The reversal of 13110100414111 is 11141400101131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13110100414111 - 217 = 13110100283039 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110100414171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 495043795 + ... + 495070276.

It is an arithmetic number, because the mean of its divisors is an integer number (3277772635356).

Almost surely, 213110100414111 is an apocalyptic number.

13110100414111 is a deficient number, since it is larger than the sum of its proper divisors (990127313).

13110100414111 is an equidigital number, since it uses as much as digits as its factorization.

13110100414111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 990127312.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 13110100414111 its reverse (11141400101131), we get a palindrome (24251500515242).

The spelling of 13110100414111 in words is "thirteen trillion, one hundred ten billion, one hundred million, four hundred fourteen thousand, one hundred eleven".

Divisors: 1 13241 990114071 13110100414111