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13110101244312 = 233171931127429563
BaseRepresentation
bin1011111011000110111011…
…1011010111100110011000
31201102022110111102020201220
42332301232323113212120
53204243441404304222
643514410344212040
72522113346625642
oct276615673274630
951368414366656
1013110101244312
1141a4a65411196
1215789aa46a020
1374137b1432a7
14334764841892
1517b0555ccb5c
hexbec6eed7998

13110101244312 has 256 divisors, whose sum is σ = 38005073510400. Its totient is φ = 3741107005440.

The previous prime is 13110101244301. The next prime is 13110101244323. The reversal of 13110101244312 is 21344210101131.

It is an interprime number because it is at equal distance from previous prime (13110101244301) and next prime (13110101244323).

It is a super-2 number, since 2×131101012443122 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 30304843 + ... + 30734405.

It is an arithmetic number, because the mean of its divisors is an integer number (148457318400).

Almost surely, 213110101244312 is an apocalyptic number.

13110101244312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13110101244312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19002536755200).

13110101244312 is an abundant number, since it is smaller than the sum of its proper divisors (24894972266088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13110101244312 is a wasteful number, since it uses less digits than its factorization.

13110101244312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 429766 (or 429762 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 13110101244312 its reverse (21344210101131), we get a palindrome (34454311345443).

The spelling of 13110101244312 in words is "thirteen trillion, one hundred ten billion, one hundred one million, two hundred forty-four thousand, three hundred twelve".