131101101013 has 4 divisors (see below), whose sum is σ = 131472492588. Its totient is φ = 130729709440.

The previous prime is 131101100983. The next prime is 131101101049. The reversal of 131101101013 is 310101101131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 87806727684 + 43294373329 = 296322^2 + 208073^2 .

It is a cyclic number.

It is not a de Polignac number, because 131101101013 - 2¹³ = 131101092821 is a prime.

It is a super-4 number, since 4×131101101013⁴ (a number of 46 digits) contains 4444 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131101100984 and 131101101002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131101101073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185695258 + ... + 185695963.

It is an arithmetic number, because the mean of its divisors is an integer number (32868123147).

Almost surely, 2^131101101013 is an apocalyptic number.

It is an amenable number.

131101101013 is a deficient number, since it is larger than the sum of its proper divisors (371391575).

131101101013 is an equidigital number, since it uses as much as digits as its factorization.

131101101013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 371391574.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 131101101013 its reverse (310101101131), we get a palindrome (441202202144).

The spelling of 131101101013 in words is "one hundred thirty-one billion, one hundred one million, one hundred one thousand, thirteen".