Base | Representation |
---|---|
bin | 11101110011110001011011… |
… | …101101001111100111000111 |
3 | 122012012010220111011201121001 |
4 | 131303301123231033213013 |
5 | 114140430043301031213 |
6 | 1142455005004034131 |
7 | 36420512656114663 |
oct | 3563613355174707 |
9 | 565163814151531 |
10 | 131101120330183 |
11 | 38855744699933 |
12 | 12854337b32947 |
13 | 581ca234ab913 |
14 | 24534843778a3 |
15 | 10253935991dd |
hex | 773c5bb4f9c7 |
131101120330183 has 2 divisors, whose sum is σ = 131101120330184. Its totient is φ = 131101120330182.
The previous prime is 131101120330181. The next prime is 131101120330247. The reversal of 131101120330183 is 381033021101131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131101120330183 - 21 = 131101120330181 is a prime.
Together with 131101120330181, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131101120330181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550560165091 + 65550560165092.
It is an arithmetic number, because the mean of its divisors is an integer number (65550560165092).
Almost surely, 2131101120330183 is an apocalyptic number.
131101120330183 is a deficient number, since it is larger than the sum of its proper divisors (1).
131101120330183 is an equidigital number, since it uses as much as digits as its factorization.
131101120330183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 28.
The spelling of 131101120330183 in words is "one hundred thirty-one trillion, one hundred one billion, one hundred twenty million, three hundred thirty thousand, one hundred eighty-three".
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