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131101123169 is a prime number
BaseRepresentation
bin111101000011000111…
…1000110001001100001
3110112101122220002122102
41322012033012021201
54121443341420134
6140121012020145
712320544105662
oct1720617061141
9415348802572
10131101123169
1150666191285
12214a9601655
13c4940597c3
1464b981b369
15362486c37e
hex1e863c6261

131101123169 has 2 divisors, whose sum is σ = 131101123170. Its totient is φ = 131101123168.

The previous prime is 131101123093. The next prime is 131101123171. The reversal of 131101123169 is 961321101131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90774458944 + 40326664225 = 301288^2 + 200815^2 .

It is a cyclic number.

It is not a de Polignac number, because 131101123169 - 212 = 131101119073 is a prime.

It is a super-2 number, since 2×1311011231692 (a number of 23 digits) contains 22 as substring.

Together with 131101123171, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131101123189) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550561584 + 65550561585.

It is an arithmetic number, because the mean of its divisors is an integer number (65550561585).

Almost surely, 2131101123169 is an apocalyptic number.

It is an amenable number.

131101123169 is a deficient number, since it is larger than the sum of its proper divisors (1).

131101123169 is an equidigital number, since it uses as much as digits as its factorization.

131101123169 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 29.

The spelling of 131101123169 in words is "one hundred thirty-one billion, one hundred one million, one hundred twenty-three thousand, one hundred sixty-nine".