131101230055501 has 4 divisors (see below), whose sum is σ = 132374057531872. Its totient is φ = 129828402579132.

The previous prime is 131101230055441. The next prime is 131101230055541. The reversal of 131101230055501 is 105550032101131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131101230055501 - 2¹⁹ = 131101229531213 is a prime.

It is a super-2 number, since 2×131101230055501² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131101230055501.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131101230055541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 636413738031 + ... + 636413738236.

It is an arithmetic number, because the mean of its divisors is an integer number (33093514382968).

Almost surely, 2^{131101230055501} is an apocalyptic number.

It is an amenable number.

131101230055501 is a deficient number, since it is larger than the sum of its proper divisors (1272827476371).

131101230055501 is a wasteful number, since it uses less digits than its factorization.

131101230055501 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1272827476370.

The product of its (nonzero) digits is 2250, while the sum is 28.

Adding to 131101230055501 its reverse (105550032101131), we get a palindrome (236651262156632).

The spelling of 131101230055501 in words is "one hundred thirty-one trillion, one hundred one billion, two hundred thirty million, fifty-five thousand, five hundred one".