Base | Representation |
---|---|
bin | 10011000100111110011… |
… | …101110000001010000111 |
3 | 11122022221202021102201022 |
4 | 103010332131300022013 |
5 | 132434423312341403 |
6 | 2442134314421355 |
7 | 163501060510364 |
oct | 23047635601207 |
9 | 4568852242638 |
10 | 1311013012103 |
11 | 465aa7738193 |
12 | 1920bb73185b |
13 | 96821929652 |
14 | 4764c08546b |
15 | 24180bd4d38 |
hex | 1313e770287 |
1311013012103 has 2 divisors, whose sum is σ = 1311013012104. Its totient is φ = 1311013012102.
The previous prime is 1311013012039. The next prime is 1311013012189. The reversal of 1311013012103 is 3012103101131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311013012103 - 26 = 1311013012039 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311013012193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655506506051 + 655506506052.
It is an arithmetic number, because the mean of its divisors is an integer number (655506506052).
Almost surely, 21311013012103 is an apocalyptic number.
1311013012103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311013012103 is an equidigital number, since it uses as much as digits as its factorization.
1311013012103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1311013012103 its reverse (3012103101131), we get a palindrome (4323116113234).
The spelling of 1311013012103 in words is "one trillion, three hundred eleven billion, thirteen million, twelve thousand, one hundred three".
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