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131101303400453 is a prime number
BaseRepresentation
bin11101110011110001100110…
…100111100110100000000101
3122012012011101020122122210102
4131303301212213212200011
5114140430432132303303
61142455035103533445
736420520341151361
oct3563614647464005
9565164336578712
10131101303400453
1138855828a69281
12128543892ba285
13581ca523b9119
1424534a07d02a1
1510253a46ac288
hex773c669e6805

131101303400453 has 2 divisors, whose sum is σ = 131101303400454. Its totient is φ = 131101303400452.

The previous prime is 131101303400443. The next prime is 131101303400467. The reversal of 131101303400453 is 354004303101131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103398839664484 + 27702463735969 = 10168522^2 + 5263313^2 .

It is a cyclic number.

It is not a de Polignac number, because 131101303400453 - 246 = 60732559222789 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131101303400443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550651700226 + 65550651700227.

It is an arithmetic number, because the mean of its divisors is an integer number (65550651700227).

Almost surely, 2131101303400453 is an apocalyptic number.

It is an amenable number.

131101303400453 is a deficient number, since it is larger than the sum of its proper divisors (1).

131101303400453 is an equidigital number, since it uses as much as digits as its factorization.

131101303400453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 131101303400453 its reverse (354004303101131), we get a palindrome (485105606501584).

The spelling of 131101303400453 in words is "one hundred thirty-one trillion, one hundred one billion, three hundred three million, four hundred thousand, four hundred fifty-three".