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1311014306477 is a prime number
BaseRepresentation
bin10011000100111110100…
…010101100001010101101
311122022221211201012021002
4103010332202230022231
5132434424130301402
62442134402250045
7163501104511151
oct23047642541255
94568854635232
101311014306477
11465aa8441717
12192100056925
1396821c90855
144764c301061
1524180d8d602
hex1313e8ac2ad

1311014306477 has 2 divisors, whose sum is σ = 1311014306478. Its totient is φ = 1311014306476.

The previous prime is 1311014306467. The next prime is 1311014306501. The reversal of 1311014306477 is 7746034101131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1150286280196 + 160728026281 = 1072514^2 + 400909^2 .

It is an emirp because it is prime and its reverse (7746034101131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311014306477 - 210 = 1311014305453 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1311014306477.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311014306467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655507153238 + 655507153239.

It is an arithmetic number, because the mean of its divisors is an integer number (655507153239).

Almost surely, 21311014306477 is an apocalyptic number.

It is an amenable number.

1311014306477 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311014306477 is an equidigital number, since it uses as much as digits as its factorization.

1311014306477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 42336, while the sum is 38.

The spelling of 1311014306477 in words is "one trillion, three hundred eleven billion, fourteen million, three hundred six thousand, four hundred seventy-seven".