Base | Representation |
---|---|
bin | 11101110011110010010001… |
… | …010101001101100100000001 |
3 | 122012012020020012001200120102 |
4 | 131303302101111031210001 |
5 | 114140433414110000001 |
6 | 1142455234143052145 |
7 | 36420544162150031 |
oct | 3563622125154401 |
9 | 565166205050512 |
10 | 131102020000001 |
11 | 38856066516106 |
12 | 128545492a1055 |
13 | 581cb379bac1b |
14 | 245352ba498c1 |
15 | 10253e755ce6b |
hex | 773c9154d901 |
131102020000001 has 8 divisors (see below), whose sum is σ = 136804609497600. Its totient is φ = 125399638975072.
The previous prime is 131102019999959. The next prime is 131102020000013. The reversal of 131102020000001 is 100000020201131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131102020000001 - 210 = 131102019998977 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131102020000201) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50832401 + ... + 53349198.
It is an arithmetic number, because the mean of its divisors is an integer number (17100576187200).
Almost surely, 2131102020000001 is an apocalyptic number.
It is an amenable number.
131102020000001 is a deficient number, since it is larger than the sum of its proper divisors (5702589497599).
131102020000001 is a wasteful number, since it uses less digits than its factorization.
131102020000001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104236335.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 131102020000001 its reverse (100000020201131), we get a palindrome (231102040201132).
The spelling of 131102020000001 in words is "one hundred thirty-one trillion, one hundred two billion, twenty million, one", and thus it is an aban number.
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