Base | Representation |
---|---|
bin | 11101110011110010011111… |
… | …010110111101111101111000 |
3 | 122012012020211120220021022201 |
4 | 131303302133112331331320 |
5 | 114140434404331411212 |
6 | 1142455313351155544 |
7 | 36420553050420454 |
oct | 3563623726757570 |
9 | 565166746807281 |
10 | 131102255341432 |
11 | 38856177347661 |
12 | 128545b4075bb4 |
13 | 581cb7469a4cb |
14 | 2453550dcb664 |
15 | 102540d048b57 |
hex | 773c9f5bdf78 |
131102255341432 has 16 divisors (see below), whose sum is σ = 246321485915760. Its totient is φ = 65416525763904.
The previous prime is 131102255341283. The next prime is 131102255341487. The reversal of 131102255341432 is 234143552201131.
It is a super-2 number, since 2×1311022553414322 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131102255341391 and 131102255341400.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16825234213 + ... + 16825242004.
It is an arithmetic number, because the mean of its divisors is an integer number (15395092869735).
Almost surely, 2131102255341432 is an apocalyptic number.
It is an amenable number.
131102255341432 is a deficient number, since it is larger than the sum of its proper divisors (115219230574328).
131102255341432 is a wasteful number, since it uses less digits than its factorization.
131102255341432 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33650476710 (or 33650476706 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 37.
The spelling of 131102255341432 in words is "one hundred thirty-one trillion, one hundred two billion, two hundred fifty-five million, three hundred forty-one thousand, four hundred thirty-two".
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