13110254159 has 2 divisors, whose sum is σ = 13110254160. Its totient is φ = 13110254158.

The previous prime is 13110254153. The next prime is 13110254161. The reversal of 13110254159 is 95145201131.

It is a strong prime.

It is an emirp because it is prime and its reverse (95145201131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13110254159 - 2⁸ = 13110253903 is a prime.

It is a super-2 number, since 2×13110254159² (a number of 21 digits) contains 22 as substring.

Together with 13110254161, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13110254153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555127079 + 6555127080.

It is an arithmetic number, because the mean of its divisors is an integer number (6555127080).

Almost surely, 2^13110254159 is an apocalyptic number.

13110254159 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110254159 is an equidigital number, since it uses as much as digits as its factorization.

13110254159 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 32.

The spelling of 13110254159 in words is "thirteen billion, one hundred ten million, two hundred fifty-four thousand, one hundred fifty-nine".