13110342401431 has 4 divisors (see below), whose sum is σ = 14302191710664. Its totient is φ = 11918493092200.

The previous prime is 13110342401417. The next prime is 13110342401449. The reversal of 13110342401431 is 13410424301131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13110342401431 - 2¹¹ = 13110342399383 is a prime.

It is a super-2 number, since 2×13110342401431² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13110342401431.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110342401231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 595924654600 + ... + 595924654621.

It is an arithmetic number, because the mean of its divisors is an integer number (3575547927666).

Almost surely, 2^{13110342401431} is an apocalyptic number.

13110342401431 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13110342401431 is a deficient number, since it is larger than the sum of its proper divisors (1191849309233).

13110342401431 is a wasteful number, since it uses less digits than its factorization.

13110342401431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1191849309232.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 13110342401431 its reverse (13410424301131), we get a palindrome (26520766702562).

The spelling of 13110342401431 in words is "thirteen trillion, one hundred ten billion, three hundred forty-two million, four hundred one thousand, four hundred thirty-one".