Search a number
-
+
1311034400197 is a prime number
BaseRepresentation
bin10011000100111111101…
…111010101110111000101
311122100000020112001122221
4103010333233111313011
5132434444301301242
62442140401052341
7163501440350344
oct23047757256705
94570006461587
101311034400197
114660088163a5
121921069270b1
13968261a7822
1447650c51b5b
1524182a0c167
hex1313fbd5dc5

1311034400197 has 2 divisors, whose sum is σ = 1311034400198. Its totient is φ = 1311034400196.

The previous prime is 1311034400173. The next prime is 1311034400233. The reversal of 1311034400197 is 7910044301131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1303309923876 + 7724476321 = 1141626^2 + 87889^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311034400197 - 215 = 1311034367429 is a prime.

It is a super-2 number, since 2×13110344001972 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311034400107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655517200098 + 655517200099.

It is an arithmetic number, because the mean of its divisors is an integer number (655517200099).

Almost surely, 21311034400197 is an apocalyptic number.

It is an amenable number.

1311034400197 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311034400197 is an equidigital number, since it uses as much as digits as its factorization.

1311034400197 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9072, while the sum is 34.

The spelling of 1311034400197 in words is "one trillion, three hundred eleven billion, thirty-four million, four hundred thousand, one hundred ninety-seven".