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1311034400219 = 2643149602149
BaseRepresentation
bin10011000100111111101…
…111010101110111011011
311122100000020112001200202
4103010333233111313123
5132434444301301334
62442140401052415
7163501440350405
oct23047757256733
94570006461622
101311034400219
11466008816415
1219210692710b
13968261a783b
1447650c51b75
1524182a0c17e
hex1313fbd5ddb

1311034400219 has 4 divisors (see below), whose sum is σ = 1311084028800. Its totient is φ = 1310984771640.

The previous prime is 1311034400197. The next prime is 1311034400233. The reversal of 1311034400219 is 9120044301131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311034400219 - 220 = 1311033351643 is a prime.

It is a super-2 number, since 2×13110344002192 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311034400191 and 1311034400200.

It is not an unprimeable number, because it can be changed into a prime (1311034400239) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24774644 + ... + 24827505.

It is an arithmetic number, because the mean of its divisors is an integer number (327771007200).

Almost surely, 21311034400219 is an apocalyptic number.

1311034400219 is a deficient number, since it is larger than the sum of its proper divisors (49628581).

1311034400219 is an equidigital number, since it uses as much as digits as its factorization.

1311034400219 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49628580.

The product of its (nonzero) digits is 2592, while the sum is 29.

The spelling of 1311034400219 in words is "one trillion, three hundred eleven billion, thirty-four million, four hundred thousand, two hundred nineteen".

Divisors: 1 26431 49602149 1311034400219