13110401412131 has 2 divisors, whose sum is σ = 13110401412132. Its totient is φ = 13110401412130.

The previous prime is 13110401412127. The next prime is 13110401412149. The reversal of 13110401412131 is 13121410401131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13110401412131 - 2² = 13110401412127 is a prime.

It is a super-2 number, since 2×13110401412131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13110401412097 and 13110401412106.

It is not a weakly prime, because it can be changed into another prime (13110401412181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555200706065 + 6555200706066.

It is an arithmetic number, because the mean of its divisors is an integer number (6555200706066).

Almost surely, 2^{13110401412131} is an apocalyptic number.

13110401412131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110401412131 is an equidigital number, since it uses as much as digits as its factorization.

13110401412131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 13110401412131 its reverse (13121410401131), we get a palindrome (26231811813262).

The spelling of 13110401412131 in words is "thirteen trillion, one hundred ten billion, four hundred one million, four hundred twelve thousand, one hundred thirty-one".