Base | Representation |
---|---|
bin | 1011111011001000000011… |
… | …0110110101000110111011 |
3 | 1201102100020110102110210221 |
4 | 2332302000312311012323 |
5 | 3204300100410404342 |
6 | 43514500251320511 |
7 | 2522123661446656 |
oct | 276620066650673 |
9 | 51370213373727 |
10 | 13110402044347 |
11 | 41a50aa191763 |
12 | 1578a73150137 |
13 | 7413c856128a |
14 | 33479278289d |
15 | 17b071be8a67 |
hex | bec80db51bb |
13110402044347 has 4 divisors (see below), whose sum is σ = 13680419524560. Its totient is φ = 12540384564136.
The previous prime is 13110402044339. The next prime is 13110402044359. The reversal of 13110402044347 is 74344020401131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13110402044347 - 23 = 13110402044339 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13110402044317) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 285008740072 + ... + 285008740117.
It is an arithmetic number, because the mean of its divisors is an integer number (3420104881140).
Almost surely, 213110402044347 is an apocalyptic number.
13110402044347 is a deficient number, since it is larger than the sum of its proper divisors (570017480213).
13110402044347 is an equidigital number, since it uses as much as digits as its factorization.
13110402044347 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 570017480212.
The product of its (nonzero) digits is 32256, while the sum is 34.
Adding to 13110402044347 its reverse (74344020401131), we get a palindrome (87454422445478).
The spelling of 13110402044347 in words is "thirteen trillion, one hundred ten billion, four hundred two million, forty-four thousand, three hundred forty-seven".
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