13110404011432 has 64 divisors (see below), whose sum is σ = 30257723825280. Its totient is φ = 5186028540672.

The previous prime is 13110404011391. The next prime is 13110404011501. The reversal of 13110404011432 is 23411040401131.

13110404011432 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 13110404011397 and 13110404011406.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6651003 + ... + 8393845.

It is an arithmetic number, because the mean of its divisors is an integer number (472776934770).

Almost surely, 2^{13110404011432} is an apocalyptic number.

It is an amenable number.

13110404011432 is an abundant number, since it is smaller than the sum of its proper divisors (17147319813848).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13110404011432 is a wasteful number, since it uses less digits than its factorization.

13110404011432 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1753202 (or 1753198 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13110404011432 its reverse (23411040401131), we get a palindrome (36521444412563).

The spelling of 13110404011432 in words is "thirteen trillion, one hundred ten billion, four hundred four million, eleven thousand, four hundred thirty-two".