Base | Representation |
---|---|
bin | 1011111011001000000011… |
… | …1110010101100101110100 |
3 | 1201102100020121010110110221 |
4 | 2332302000332111211310 |
5 | 3204300101411344104 |
6 | 43514500401424124 |
7 | 2522124014254516 |
oct | 276620076254564 |
9 | 51370217113427 |
10 | 13110404012404 |
11 | 41a5100306356 |
12 | 1578a7393b044 |
13 | 7413c8a9ccca |
14 | 334792b35bb6 |
15 | 17b071e86c54 |
hex | bec80f95974 |
13110404012404 has 6 divisors (see below), whose sum is σ = 22943207021714. Its totient is φ = 6555202006200.
The previous prime is 13110404012287. The next prime is 13110404012471. The reversal of 13110404012404 is 40421040401131.
It can be written as a sum of positive squares in only one way, i.e., 12386880250000 + 723523762404 = 3519500^2 + 850602^2 .
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1638800501547 + ... + 1638800501554.
Almost surely, 213110404012404 is an apocalyptic number.
It is an amenable number.
13110404012404 is a deficient number, since it is larger than the sum of its proper divisors (9832803009310).
13110404012404 is a wasteful number, since it uses less digits than its factorization.
13110404012404 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3277601003105 (or 3277601003103 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 13110404012404 its reverse (40421040401131), we get a palindrome (53531444413535).
The spelling of 13110404012404 in words is "thirteen trillion, one hundred ten billion, four hundred four million, twelve thousand, four hundred four".
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