Base | Representation |
---|---|
bin | 11101110011110100010011… |
… | …100000111010000101011110 |
3 | 122012012102212101211200001020 |
4 | 131303310103200322011132 |
5 | 114141002402222312110 |
6 | 1142500235004025010 |
7 | 36420652252552203 |
oct | 3563642340720536 |
9 | 565172771750036 |
10 | 131104204104030 |
11 | 38856a87378863 |
12 | 12854a58832166 |
13 | 58200c5345181 |
14 | 2453697b49caa |
15 | 10254c4189d70 |
hex | 773d1383a15e |
131104204104030 has 64 divisors (see below), whose sum is σ = 314806089931776. Its totient is φ = 34943792112000.
The previous prime is 131104204104019. The next prime is 131104204104127. The reversal of 131104204104030 is 30401402401131.
131104204104030 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 495777745 + ... + 496042115.
It is an arithmetic number, because the mean of its divisors is an integer number (4918845155184).
Almost surely, 2131104204104030 is an apocalyptic number.
131104204104030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131104204104030 is an abundant number, since it is smaller than the sum of its proper divisors (183701885827746).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131104204104030 is a wasteful number, since it uses less digits than its factorization.
131104204104030 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 272513.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 131104204104030 its reverse (30401402401131), we get a palindrome (161505606505161).
The spelling of 131104204104030 in words is "one hundred thirty-one trillion, one hundred four billion, two hundred four million, one hundred four thousand, thirty".
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