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1311044050331 is a prime number
BaseRepresentation
bin10011000101000000010…
…100001001110110011011
311122100000220200100011022
4103011000110021312123
5132440004234102311
62442141343553055
7163501615362011
oct23050024116633
94570026610138
101311044050331
11466013207714
12192109bbb78b
13968281a6072
14476522448b1
15241837b65db
hex13140509d9b

1311044050331 has 2 divisors, whose sum is σ = 1311044050332. Its totient is φ = 1311044050330.

The previous prime is 1311044050307. The next prime is 1311044050439. The reversal of 1311044050331 is 1330504401131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1311044050331 is a prime.

It is a super-2 number, since 2×13110440503312 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1311044050331.

It is not a weakly prime, because it can be changed into another prime (1311044050031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655522025165 + 655522025166.

It is an arithmetic number, because the mean of its divisors is an integer number (655522025166).

Almost surely, 21311044050331 is an apocalyptic number.

1311044050331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311044050331 is an equidigital number, since it uses as much as digits as its factorization.

1311044050331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 1311044050331 its reverse (1330504401131), we get a palindrome (2641548451462).

The spelling of 1311044050331 in words is "one trillion, three hundred eleven billion, forty-four million, fifty thousand, three hundred thirty-one".