13110441122533 has 4 divisors (see below), whose sum is σ = 13110545927808. Its totient is φ = 13110336317260.

The previous prime is 13110441122423. The next prime is 13110441122539. The reversal of 13110441122533 is 33522114401131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13110441122533 - 2¹³ = 13110441114341 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13110441122495 and 13110441122504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110441122539) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52214773 + ... + 52465258.

It is an arithmetic number, because the mean of its divisors is an integer number (3277636481952).

Almost surely, 2^{13110441122533} is an apocalyptic number.

It is an amenable number.

13110441122533 is a deficient number, since it is larger than the sum of its proper divisors (104805275).

13110441122533 is a wasteful number, since it uses less digits than its factorization.

13110441122533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 104805274.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 13110441122533 its reverse (33522114401131), we get a palindrome (46632555523664).

The spelling of 13110441122533 in words is "thirteen trillion, one hundred ten billion, four hundred forty-one million, one hundred twenty-two thousand, five hundred thirty-three".