13110554035 has 4 divisors (see below), whose sum is σ = 15732664848. Its totient is φ = 10488443224.

The previous prime is 13110553993. The next prime is 13110554077. The reversal of 13110554035 is 53045501131.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13110553993) and next prime (13110554077).

It is a cyclic number.

It is not a de Polignac number, because 13110554035 - 2⁹ = 13110553523 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13110553994 and 13110554012.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1311055399 + ... + 1311055408.

It is an arithmetic number, because the mean of its divisors is an integer number (3933166212).

Almost surely, 2^13110554035 is an apocalyptic number.

13110554035 is a deficient number, since it is larger than the sum of its proper divisors (2622110813).

13110554035 is an equidigital number, since it uses as much as digits as its factorization.

13110554035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2622110812.

The product of its (nonzero) digits is 4500, while the sum is 28.

The spelling of 13110554035 in words is "thirteen billion, one hundred ten million, five hundred fifty-four thousand, thirty-five".