1311100103303 has 4 divisors (see below), whose sum is σ = 1311149166960. Its totient is φ = 1311051039648.

The previous prime is 1311100103297. The next prime is 1311100103309. The reversal of 1311100103303 is 3033010011131.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1311100103297) and next prime (1311100103309).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311100103303 is a prime.

It is a super-3 number, since 3×1311100103303³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311100103309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24491723 + ... + 24545196.

It is an arithmetic number, because the mean of its divisors is an integer number (327787291740).

Almost surely, 2^{1311100103303} is an apocalyptic number.

1311100103303 is a deficient number, since it is larger than the sum of its proper divisors (49063657).

1311100103303 is an equidigital number, since it uses as much as digits as its factorization.

1311100103303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49063656.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 1311100103303 its reverse (3033010011131), we get a palindrome (4344110114434).

The spelling of 1311100103303 in words is "one trillion, three hundred eleven billion, one hundred million, one hundred three thousand, three hundred three".