1311100113133 has 4 divisors (see below), whose sum is σ = 1311150568000. Its totient is φ = 1311049658268.

The previous prime is 1311100113121. The next prime is 1311100113151. The reversal of 1311100113133 is 3313110011131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311100113133 - 2²⁹ = 1310563242221 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1311100113133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311100113233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25188435 + ... + 25240432.

It is an arithmetic number, because the mean of its divisors is an integer number (327787642000).

Almost surely, 2^{1311100113133} is an apocalyptic number.

It is an amenable number.

1311100113133 is a deficient number, since it is larger than the sum of its proper divisors (50454867).

1311100113133 is an equidigital number, since it uses as much as digits as its factorization.

1311100113133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50454866.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 1311100113133 its reverse (3313110011131), we get a palindrome (4624210124264).

The spelling of 1311100113133 in words is "one trillion, three hundred eleven billion, one hundred million, one hundred thirteen thousand, one hundred thirty-three".