1311100222231 has 4 divisors (see below), whose sum is σ = 1311136097872. Its totient is φ = 1311064346592.

The previous prime is 1311100222141. The next prime is 1311100222253. The reversal of 1311100222231 is 1322220011131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311100222231 - 2²¹ = 1311098125079 is a prime.

It is a super-2 number, since 2×1311100222231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311100222199 and 1311100222208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311100222261) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17882946 + ... + 17956111.

It is an arithmetic number, because the mean of its divisors is an integer number (327784024468).

Almost surely, 2^{1311100222231} is an apocalyptic number.

1311100222231 is a deficient number, since it is larger than the sum of its proper divisors (35875641).

1311100222231 is an equidigital number, since it uses as much as digits as its factorization.

1311100222231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35875640.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1311100222231 its reverse (1322220011131), we get a palindrome (2633320233362).

The spelling of 1311100222231 in words is "one trillion, three hundred eleven billion, one hundred million, two hundred twenty-two thousand, two hundred thirty-one".