Base | Representation |
---|---|
bin | 10011000101000011101… |
… | …101011001101001110111 |
3 | 11122100011212211200211211 |
4 | 103011003231121221313 |
5 | 132440113324002221 |
6 | 2442151140342251 |
7 | 163503206423644 |
oct | 23050355315167 |
9 | 4570155750754 |
10 | 1311101000311 |
11 | 466042375013 |
12 | 1921250a4987 |
13 | 96836c2598b |
14 | 47659a2adcb |
15 | 241887b56e1 |
hex | 13143b59a77 |
1311101000311 has 2 divisors, whose sum is σ = 1311101000312. Its totient is φ = 1311101000310.
The previous prime is 1311101000303. The next prime is 1311101000353. The reversal of 1311101000311 is 1130001011131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311101000311 - 23 = 1311101000303 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1311101000291 and 1311101000300.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311101000381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655550500155 + 655550500156.
It is an arithmetic number, because the mean of its divisors is an integer number (655550500156).
Almost surely, 21311101000311 is an apocalyptic number.
1311101000311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311101000311 is an equidigital number, since it uses as much as digits as its factorization.
1311101000311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9, while the sum is 13.
Adding to 1311101000311 its reverse (1130001011131), we get a palindrome (2441102011442).
The spelling of 1311101000311 in words is "one trillion, three hundred eleven billion, one hundred one million, three hundred eleven", and thus it is an aban number.
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