131110112330 has 8 divisors (see below), whose sum is σ = 235998202212. Its totient is φ = 52444044928.

The previous prime is 131110112321. The next prime is 131110112339. The reversal of 131110112330 is 33211011131.

It is an interprime number because it is at equal distance from previous prime (131110112321) and next prime (131110112339).

It can be written as a sum of positive squares in 2 ways, for example, as 129521531881 + 1588580449 = 359891^2 + 39857^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 131110112299 and 131110112308.

It is not an unprimeable number, because it can be changed into a prime (131110112339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6555505607 + ... + 6555505626.

Almost surely, 2^131110112330 is an apocalyptic number.

131110112330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131110112330 is a deficient number, since it is larger than the sum of its proper divisors (104888089882).

131110112330 is a wasteful number, since it uses less digits than its factorization.

131110112330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13111011240.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 131110112330 its reverse (33211011131), we get a palindrome (164321123461).

The spelling of 131110112330 in words is "one hundred thirty-one billion, one hundred ten million, one hundred twelve thousand, three hundred thirty".