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1311101166145 = 5577494391939
BaseRepresentation
bin10011000101000011101…
…110000010001001000001
311122100011220011010022211
4103011003232002021001
5132440113344304040
62442151144102121
7163503211014301
oct23050356021101
94570156133284
101311101166145
11466042478671
12192125164941
1396836c832c4
1447659a71601
15241887e98ea
hex13143b82241

1311101166145 has 16 divisors (see below), whose sum is σ = 1576384116480. Its totient is φ = 1046839901184.

The previous prime is 1311101166139. The next prime is 1311101166149. The reversal of 1311101166145 is 5416611011131.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 1311101166145 - 225 = 1311067611713 is a prime.

It is a super-2 number, since 2×13111011661452 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1311101166149) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14214586 + ... + 14306524.

It is an arithmetic number, because the mean of its divisors is an integer number (98524007280).

Almost surely, 21311101166145 is an apocalyptic number.

It is an amenable number.

1311101166145 is a deficient number, since it is larger than the sum of its proper divisors (265282950335).

1311101166145 is an equidigital number, since it uses as much as digits as its factorization.

1311101166145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 97464.

The product of its (nonzero) digits is 2160, while the sum is 31.

Adding to 1311101166145 its reverse (5416611011131), we get a palindrome (6727712177276).

The spelling of 1311101166145 in words is "one trillion, three hundred eleven billion, one hundred one million, one hundred sixty-six thousand, one hundred forty-five".

Divisors: 1 5 577 2885 4943 24715 91939 459695 2852111 14260555 53048803 265244015 454454477 2272272385 262220233229 1311101166145