Base | Representation |
---|---|
bin | 11101110011111001111111… |
… | …100001010101000001101000 |
3 | 122012020000122000021021101221 |
4 | 131303321333201111001220 |
5 | 114141102404121333000 |
6 | 1142503125002351424 |
7 | 36421256506416331 |
oct | 3563717741250150 |
9 | 565200560237357 |
10 | 131110311121000 |
11 | 38859630653022 |
12 | 12856081abb574 |
13 | 5820859640593 |
14 | 2453ab6c55288 |
15 | 10257303b161a |
hex | 773e7f855068 |
131110311121000 has 32 divisors (see below), whose sum is σ = 306798128025480. Its totient is φ = 52444124448000.
The previous prime is 131110311120977. The next prime is 131110311121003. The reversal of 131110311121000 is 121113011131.
It can be written as a sum of positive squares in 4 ways, for example, as 55849585134564 + 75260725986436 = 7473258^2 + 8675294^2 .
It is not an unprimeable number, because it can be changed into a prime (131110311121003) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 65555154561 + ... + 65555156560.
Almost surely, 2131110311121000 is an apocalyptic number.
131110311121000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131110311121000 is an abundant number, since it is smaller than the sum of its proper divisors (175687816904480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131110311121000 is a wasteful number, since it uses less digits than its factorization.
131110311121000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 131110311142 (or 131110311128 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 16.
Adding to 131110311121000 its reverse (121113011131), we get a palindrome (131231424132131).
The spelling of 131110311121000 in words is "one hundred thirty-one trillion, one hundred ten billion, three hundred eleven million, one hundred twenty-one thousand".
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