Base | Representation |
---|---|
bin | 1011111011001010101001… |
… | …1101101101001001100111 |
3 | 1201102102001002221102211022 |
4 | 2332302222131231021213 |
5 | 3204303013111214343 |
6 | 43515053425201355 |
7 | 2522150166026135 |
oct | 276625235551147 |
9 | 51372032842738 |
10 | 13111100101223 |
11 | 41a5428224173 |
12 | 1579028a9025b |
13 | 7414aa070097 |
14 | 33481b372755 |
15 | 17b0b3135568 |
hex | becaa76d267 |
13111100101223 has 2 divisors, whose sum is σ = 13111100101224. Its totient is φ = 13111100101222.
The previous prime is 13111100101199. The next prime is 13111100101289. The reversal of 13111100101223 is 32210100111131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13111100101223 - 212 = 13111100097127 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13111100109223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555550050611 + 6555550050612.
It is an arithmetic number, because the mean of its divisors is an integer number (6555550050612).
Almost surely, 213111100101223 is an apocalyptic number.
13111100101223 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111100101223 is an equidigital number, since it uses as much as digits as its factorization.
13111100101223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 13111100101223 its reverse (32210100111131), we get a palindrome (45321200212354).
The spelling of 13111100101223 in words is "thirteen trillion, one hundred eleven billion, one hundred million, one hundred one thousand, two hundred twenty-three".
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