Base | Representation |
---|---|
bin | 1011111011001010101001… |
… | …1110011110001111011101 |
3 | 1201102102001010022122122122 |
4 | 2332302222132132033131 |
5 | 3204303013134133201 |
6 | 43515053433352325 |
7 | 2522150200524311 |
oct | 276625236361735 |
9 | 51372033278578 |
10 | 13111100302301 |
11 | 41a5428351251 |
12 | 1579028b686a5 |
13 | 7414aa110771 |
14 | 33481b3c5b41 |
15 | 17b0b3174e1b |
hex | becaa79e3dd |
13111100302301 has 4 divisors (see below), whose sum is σ = 13882341496572. Its totient is φ = 12339859108032.
The previous prime is 13111100302291. The next prime is 13111100302309. The reversal of 13111100302301 is 10320300111131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 5007547440025 + 8103552862276 = 2237755^2 + 2846674^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13111100302301 is a prime.
It is a super-2 number, since 2×131111003023012 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (17), and also a Moran number because the ratio is a prime number: 771241194253 = 13111100302301 / (1 + 3 + 1 + 1 + 1 + 1 + 0 + 0 + 3 + 0 + 2 + 3 + 0 + 1).
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13111100302301.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13111100302309) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385620597110 + ... + 385620597143.
It is an arithmetic number, because the mean of its divisors is an integer number (3470585374143).
Almost surely, 213111100302301 is an apocalyptic number.
It is an amenable number.
13111100302301 is a deficient number, since it is larger than the sum of its proper divisors (771241194271).
13111100302301 is an equidigital number, since it uses as much as digits as its factorization.
13111100302301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 771241194270.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 13111100302301 its reverse (10320300111131), we get a palindrome (23431400413432).
The spelling of 13111100302301 in words is "thirteen trillion, one hundred eleven billion, one hundred million, three hundred two thousand, three hundred one".
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