1311110320031 has 4 divisors (see below), whose sum is σ = 1311121985064. Its totient is φ = 1311098655000.

The previous prime is 1311110320027. The next prime is 1311110320087. The reversal of 1311110320031 is 1300230111131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311110320031 - 2² = 1311110320027 is a prime.

It is a super-2 number, since 2×1311110320031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311110319991 and 1311110320009.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311110350031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5662265 + ... + 5889266.

It is an arithmetic number, because the mean of its divisors is an integer number (327780496266).

Almost surely, 2^{1311110320031} is an apocalyptic number.

1311110320031 is a deficient number, since it is larger than the sum of its proper divisors (11665033).

1311110320031 is a wasteful number, since it uses less digits than its factorization.

1311110320031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11665032.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1311110320031 its reverse (1300230111131), we get a palindrome (2611340431162).

The spelling of 1311110320031 in words is "one trillion, three hundred eleven billion, one hundred ten million, three hundred twenty thousand, thirty-one".