Search a number
-
+
13111110312233 is a prime number
BaseRepresentation
bin1011111011001010101100…
…0100101010000100101001
31201102102001211011012200212
42332302223010222010221
53204303023214442413
643515054432110505
72522150351564633
oct276625304520451
951372054135625
1013111110312233
1141a5432a6891a
121579030395435
137414ac2069bb
1433481c86da53
1517b0b3ea0ca8
hexbecab12a129

13111110312233 has 2 divisors, whose sum is σ = 13111110312234. Its totient is φ = 13111110312232.

The previous prime is 13111110312161. The next prime is 13111110312239. The reversal of 13111110312233 is 33221301111131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12312610798489 + 798499513744 = 3508933^2 + 893588^2 .

It is a cyclic number.

It is not a de Polignac number, because 13111110312233 - 210 = 13111110311209 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13111110312199 and 13111110312208.

It is not a weakly prime, because it can be changed into another prime (13111110312239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555555156116 + 6555555156117.

It is an arithmetic number, because the mean of its divisors is an integer number (6555555156117).

Almost surely, 213111110312233 is an apocalyptic number.

It is an amenable number.

13111110312233 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111110312233 is an equidigital number, since it uses as much as digits as its factorization.

13111110312233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 13111110312233 its reverse (33221301111131), we get a palindrome (46332411423364).

The spelling of 13111110312233 in words is "thirteen trillion, one hundred eleven billion, one hundred ten million, three hundred twelve thousand, two hundred thirty-three".