1311111125111 has 2 divisors, whose sum is σ = 1311111125112. Its totient is φ = 1311111125110.

The previous prime is 1311111125017. The next prime is 1311111125141. The reversal of 1311111125111 is 1115211111131.

It is a m-pointer prime, because the next prime (1311111125141) can be obtained adding 1311111125111 to its product of digits (30).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1311111125111 - 2¹⁰ = 1311111124087 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311111125141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655555562555 + 655555562556.

It is an arithmetic number, because the mean of its divisors is an integer number (655555562556).

Almost surely, 2^{1311111125111} is an apocalyptic number.

1311111125111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311111125111 is an equidigital number, since it uses as much as digits as its factorization.

1311111125111 is an evil number, because the sum of its binary digits is even.

The product of its digits is 30, while the sum is 20.

Adding to 1311111125111 its reverse (1115211111131), we get a palindrome (2426322236242).

The spelling of 1311111125111 in words is "one trillion, three hundred eleven billion, one hundred eleven million, one hundred twenty-five thousand, one hundred eleven".