131111140324111 has 4 divisors (see below), whose sum is σ = 131111287840800. Its totient is φ = 131110992807424.

The previous prime is 131111140324103. The next prime is 131111140324133. The reversal of 131111140324111 is 111423041111131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131111140324111 - 2³ = 131111140324103 is a prime.

It is a super-2 number, since 2×131111140324111² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131111140322111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72417031 + ... + 74205448.

It is an arithmetic number, because the mean of its divisors is an integer number (32777821960200).

Almost surely, 2^{131111140324111} is an apocalyptic number.

131111140324111 is a deficient number, since it is larger than the sum of its proper divisors (147516689).

131111140324111 is an equidigital number, since it uses as much as digits as its factorization.

131111140324111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 147516688.

The product of its (nonzero) digits is 288, while the sum is 25.

Adding to 131111140324111 its reverse (111423041111131), we get a palindrome (242534181435242).

The spelling of 131111140324111 in words is "one hundred thirty-one trillion, one hundred eleven billion, one hundred forty million, three hundred twenty-four thousand, one hundred eleven".