13111114341013 has 32 divisors (see below), whose sum is σ = 15323896707840. Its totient is φ = 11112299642880.

The previous prime is 13111114340983. The next prime is 13111114341047. The reversal of 13111114341013 is 31014341111131.

13111114341013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 13111114341013 - 2⁵ = 13111114340981 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111114341313) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 442393 + ... + 5139838.

It is an arithmetic number, because the mean of its divisors is an integer number (478871772120).

Almost surely, 2^{13111114341013} is an apocalyptic number.

13111114341013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13111114341013 is a deficient number, since it is larger than the sum of its proper divisors (2212782366827).

13111114341013 is a wasteful number, since it uses less digits than its factorization.

13111114341013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5582557.

The product of its (nonzero) digits is 432, while the sum is 25.

Adding to 13111114341013 its reverse (31014341111131), we get a palindrome (44125455452144).

The spelling of 13111114341013 in words is "thirteen trillion, one hundred eleven billion, one hundred fourteen million, three hundred forty-one thousand, thirteen".