131111220320023 has 4 divisors (see below), whose sum is σ = 136811708160048. Its totient is φ = 125410732480000.

The previous prime is 131111220319999. The next prime is 131111220320077. The reversal of 131111220320023 is 320023022111131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131111220320023 - 2¹³ = 131111220311831 is a prime.

It is a super-2 number, since 2×131111220320023² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131111220319976 and 131111220320003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131111220320923) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2850243919978 + ... + 2850243920023.

It is an arithmetic number, because the mean of its divisors is an integer number (34202927040012).

Almost surely, 2^{131111220320023} is an apocalyptic number.

131111220320023 is a deficient number, since it is larger than the sum of its proper divisors (5700487840025).

131111220320023 is an equidigital number, since it uses as much as digits as its factorization.

131111220320023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5700487840024.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 131111220320023 its reverse (320023022111131), we get a palindrome (451134242431154).

The spelling of 131111220320023 in words is "one hundred thirty-one trillion, one hundred eleven billion, two hundred twenty million, three hundred twenty thousand, twenty-three".