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13111128493 is a prime number
BaseRepresentation
bin11000011010111101…
…11111000110101101
31020211201220100002121
430031132333012231
5203322422102433
610005000552541
7642622516261
oct141536770655
936751810077
1013111128493
115618987991
12265aa82751
13130c4108c8
148c54160a1
1551b0a3c2d
hex30d7bf1ad

13111128493 has 2 divisors, whose sum is σ = 13111128494. Its totient is φ = 13111128492.

The previous prime is 13111128479. The next prime is 13111128509. The reversal of 13111128493 is 39482111131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12281515684 + 829612809 = 110822^2 + 28803^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13111128493 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111128193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555564246 + 6555564247.

It is an arithmetic number, because the mean of its divisors is an integer number (6555564247).

Almost surely, 213111128493 is an apocalyptic number.

It is an amenable number.

13111128493 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111128493 is an equidigital number, since it uses as much as digits as its factorization.

13111128493 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5184, while the sum is 34.

The spelling of 13111128493 in words is "thirteen billion, one hundred eleven million, one hundred twenty-eight thousand, four hundred ninety-three".