Base | Representation |
---|---|
bin | 11000011010111101… |
… | …11111000110101101 |
3 | 1020211201220100002121 |
4 | 30031132333012231 |
5 | 203322422102433 |
6 | 10005000552541 |
7 | 642622516261 |
oct | 141536770655 |
9 | 36751810077 |
10 | 13111128493 |
11 | 5618987991 |
12 | 265aa82751 |
13 | 130c4108c8 |
14 | 8c54160a1 |
15 | 51b0a3c2d |
hex | 30d7bf1ad |
13111128493 has 2 divisors, whose sum is σ = 13111128494. Its totient is φ = 13111128492.
The previous prime is 13111128479. The next prime is 13111128509. The reversal of 13111128493 is 39482111131.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12281515684 + 829612809 = 110822^2 + 28803^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13111128493 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13111128193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555564246 + 6555564247.
It is an arithmetic number, because the mean of its divisors is an integer number (6555564247).
Almost surely, 213111128493 is an apocalyptic number.
It is an amenable number.
13111128493 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111128493 is an equidigital number, since it uses as much as digits as its factorization.
13111128493 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5184, while the sum is 34.
The spelling of 13111128493 in words is "thirteen billion, one hundred eleven million, one hundred twenty-eight thousand, four hundred ninety-three".
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