Base | Representation |
---|---|
bin | 11000011010111110… |
… | …00101010111100001 |
3 | 1020211201221122021200 |
4 | 30031133011113201 |
5 | 203322423413040 |
6 | 10005001311413 |
7 | 642622654125 |
oct | 141537052741 |
9 | 36751848250 |
10 | 13111154145 |
11 | 56189a5191 |
12 | 265aa95569 |
13 | 130c41c49b |
14 | 8c5421585 |
15 | 51b0ab630 |
hex | 30d7c55e1 |
13111154145 has 48 divisors (see below), whose sum is σ = 22838205312. Its totient is φ = 6958195200.
The previous prime is 13111154131. The next prime is 13111154159. The reversal of 13111154145 is 54145111131.
It is a happy number.
13111154145 is a `hidden beast` number, since 1 + 3 + 1 + 111 + 541 + 4 + 5 = 666.
It is an interprime number because it is at equal distance from previous prime (13111154131) and next prime (13111154159).
It is not a de Polignac number, because 13111154145 - 215 = 13111121377 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 11674554 + ... + 11675676.
It is an arithmetic number, because the mean of its divisors is an integer number (475795944).
Almost surely, 213111154145 is an apocalyptic number.
13111154145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13111154145 is a deficient number, since it is larger than the sum of its proper divisors (9727051167).
13111154145 is a wasteful number, since it uses less digits than its factorization.
13111154145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2182 (or 2179 counting only the distinct ones).
The product of its digits is 1200, while the sum is 27.
Adding to 13111154145 its reverse (54145111131), we get a palindrome (67256265276).
The spelling of 13111154145 in words is "thirteen billion, one hundred eleven million, one hundred fifty-four thousand, one hundred forty-five".
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