Base | Representation |
---|---|
bin | 11101110011111011100101… |
… | …111111000110100011110111 |
3 | 122012020012001211000122100102 |
4 | 131303323211333012203313 |
5 | 114141114414212431403 |
6 | 1142504011332304315 |
7 | 36421350222362516 |
oct | 3563734577064367 |
9 | 565205054018312 |
10 | 131112030202103 |
11 | 3885a332a69105 |
12 | 1285648177209b |
13 | 5820a7183ac32 |
14 | 2453bdb2a667d |
15 | 10257d1283b88 |
hex | 773ee5fc68f7 |
131112030202103 has 2 divisors, whose sum is σ = 131112030202104. Its totient is φ = 131112030202102.
The previous prime is 131112030202037. The next prime is 131112030202133. The reversal of 131112030202103 is 301202030211131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131112030202103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131112030202133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65556015101051 + 65556015101052.
It is an arithmetic number, because the mean of its divisors is an integer number (65556015101052).
Almost surely, 2131112030202103 is an apocalyptic number.
131112030202103 is a deficient number, since it is larger than the sum of its proper divisors (1).
131112030202103 is an equidigital number, since it uses as much as digits as its factorization.
131112030202103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 131112030202103 its reverse (301202030211131), we get a palindrome (432314060413234).
The spelling of 131112030202103 in words is "one hundred thirty-one trillion, one hundred twelve billion, thirty million, two hundred two thousand, one hundred three".
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